# A container with a volume of 18 L contains a gas with a temperature of 280^o C. If the temperature of the gas changes to 360 ^o K without any change in pressure, what must the container's new volume be?

Aug 29, 2016

We use Charles' Law: ${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$, where $T$ is quoted using Absolute Temperature.

#### Explanation:

The container was clearly a piston, because its volume changed during the experiment.

${T}_{1} = 280 + 273 K = 553 K$; ${T}_{2} = 360 + 273 K = 633 K$

${V}_{2} = \frac{18 \cdot L \times 633 \cdot K}{553 \cdot K}$ $=$ ??L

Reasonably, volume has increased.