# A container with a volume of 6 L contains a gas with a temperature of 560^o K. If the temperature of the gas changes to 480 ^o K without any change in pressure, what must the container's new volume be?

Mar 2, 2018

The new volume is $= 5.14 L$

#### Explanation:

Apply Charles' Law

$\text{Volume"/"Temperature"="Constant}$, at $\text{Constant Pressure}$

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

The initial temperature is ${T}_{1} = 560 K$

The final temperature is ${T}_{2} = 480 K$

The initial tvolume is ${V}_{1} = 6 L$

The final volume is

${V}_{2} = {T}_{2} / {T}_{1} \cdot {V}_{1} = \frac{480}{560} \cdot 6 = 5.14 L$