Question

A container with a volume of `6 L` contains a gas with a temperature of `620^o K`. If the temperature of the gas changes to `370 ^o K` without any change in pressure, what must the container's new volume be?

Answer 1

Container's new volume will be `3.58L`.

Explanation:

When a fixed quantum (mass) of gas in a container under goes changes in its pressure, volume and temperature, `(PV)/T` always remains constant, where `p` is pressure , `V` is volume and `T` is its temperature in degree Kelvins.

Here there is no change n pressure, hence `V/T` is constant i.e. `V_i/T_i=V_f/T_f`,

where `V_i` and `T_i` are initial volume and temperature and `V_f` and `T_f` are final volume and temperature.

As `V_i=6L` and `T_i=620^@` `K` and `T_f=370^@` `and`V_f# is given by

`6/620=V_f/370` and `V_f=(6xx370)/620=3.58L`