A container with a volume of #6 L# contains a gas with a temperature of #620^o K#. If the temperature of the gas changes to #370 ^o K# without any change in pressure, what must the container's new volume be?

1 Answer
Dec 21, 2016

Answer:

Container's new volume will be #3.58L#.

Explanation:

When a fixed quantum (mass) of gas in a container under goes changes in its pressure, volume and temperature, #(PV)/T# always remains constant, where #p# is pressure , #V# is volume and #T# is its temperature in degree Kelvins.

Here there is no change n pressure, hence #V/T# is constant i.e. #V_i/T_i=V_f/T_f#,

where #V_i# and #T_i# are initial volume and temperature and #V_f# and #T_f# are final volume and temperature.

As #V_i=6L# and #T_i=620^@# #K# and #T_f=370^@## and #V_f# is given by

#6/620=V_f/370# and #V_f=(6xx370)/620=3.58L#