A container with a volume of 6 L contains a gas with a temperature of 720^o K. If the temperature of the gas changes to 480 ^o K without any change in pressure, what must the container's new volume be?

Sep 21, 2016

Use Charles' Law to find the new volume is $4 L$.

Explanation:

According to Charles' Law, in an ideal gas at constant pressure, volume is directly proportional to temperature. The relationship can be expressed as

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

${V}_{1} = 6 L$, ${T}_{1} = 720 K$, ${V}_{2} =$?, ${T}_{2} = 480 K$

$\frac{6}{720} = {V}_{2} / 480$

Cross multiply:

$6 \cdot 480 = 720 \cdot {V}_{2}$

Divide both sides by $720$

$\frac{6 \cdot 480}{720} = \frac{720 \cdot {V}_{2}}{720}$

${V}_{2} = 4 L$