Question

A crate with a mass of 12kg is sliding across the floor with a velocity of 8.8m/s. If the coefficient of kinetic friction is 0.16, how far will it slide before coming to rest?

please show all of your work

Answer 1

Given

`v->"Velocity of the crate"=8.8"m/s"`

`m->"Mass of the crate"=12kg`

`mu->"Coefficient of kinetic frixtion"=0.16`

`"Let the crate slides x m before coming to rest"`

By consudering conservation of energy we can write

`mumgx=1/2mv^2`

`=>x=v^2/(2mug)=8.8^2/(2xx0.16xx9.8)m~~24.7m`