# A current of 3.03 A is passed through a Pb(NO_3)_2 solution for 1.20 hours. How much lead is plated out of the solution?

May 14, 2016

$\approx 14 g$

#### Explanation:

We know from Faraday;s law of electrolysis the mass of a substance (in g ) deposited at any electrode is given by

$w = \frac{E c t}{F} \text{ }$ where

• $E = \text{equivalent mass of ion "Pb^(2+) ="molar mass"/"valency"=207/2=103.5g/"equivalent }$
• $c = C u r r e n t = 3.03 A$
• $t = T i m e = 1.2 h r s = 1.2 \times 60 \times 60 s = 4320 s$
• $F = 96500 C$
• $w = \frac{E c t}{F} = \frac{103.5 \times 3.03 \times 4320}{96500} g \approx 14 g$