A cylinder has inner and outer radii of #13 cm# and #15 cm#, respectively, and a mass of #6 kg#. If the cylinder's frequency of counterclockwise rotation about its center changes from #2 Hz# to #3 Hz#, by how much does its angular momentum change?

Question

1242 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-30T15:02:16

The answer is #=0.74kgms^(-1)#

The angular momentum is #L=Iomega#

The change in angular momentum is

#DeltaL=I Delta omega#

For a cylinder, #I=(m(r_1^2+r_2^2))/2#

So, #I=6*(0.13^2+0.15^2)/2=0.1182kgm^2#

#Delta omega=(3-2)*2pi#

#DeltaL=0.1182*2pi=0.74kgms^(-1)#