A cylinder has inner and outer radii of #16 cm# and #18 cm#, respectively, and a mass of #2 kg#. If the cylinder's frequency of rotation about its center changes from #4 Hz# to #9 Hz#, by how much does its angular momentum change?

1 Answer
Oct 27, 2017

Answer:

The change in angular momentum is #=1.82kgm^2s^-1#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

and #omega# is the angular velocity

The mass of the cylinder is #m=2kg#

The radii of the cylinder are #r_1=0.16m# and #r_2=0.18m#

For the cylinder, the moment of inertia is #I=m(r_1^2+r_2^2)/2#

So, #I=2*(0.16^2+0.18^2)/2=0.058kgm^2#

The change in angular velocity is

#Delta omega=Deltaf*2pi=(9-4)*2pi=10pirads^-1#

The change in angular momentum is

#DeltaL=IDelta omega=0.058 xx10pi=1.82kgm^2s^-1#