A cylinder has inner and outer radii of #2 cm# and #3 cm#, respectively, and a mass of #1 kg#. If the cylinder's frequency of counterclockwise rotation about its center changes from #10 Hz# to #15 Hz#, by how much does its angular momentum change?

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Apr 24, 2018

Answer:

The change in angular momentum is #=0.041kgm^2s^-1#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

and #omega# is the angular velocity

The mass of the cylinder is #m=1kg#

The radii of the cylinder are #r_1=0.02m# and #r_2=0.03m#

For the cylinder, the moment of inertia is #I=m((r_1^2+r_2^2))/2#

So, #I=1*((0.02^2+0.03^2))/2=0.0013kgm^2#

The change in angular velocity is

#Delta omega=Deltaf*2pi=(15-10) xx2pi=10pirads^-1#

The change in angular momentum is

#DeltaL=IDelta omega=0.0013xx10pi=0.041kgm^2s^-1#

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