A cylinder has inner and outer radii of #4 cm# and #5 cm#, respectively, and a mass of #5 kg#. If the cylinder's frequency of counterclockwise rotation about its center changes from #7 Hz# to #9 Hz#, by how much does its angular momentum change?

1 Answer
Jun 28, 2017

The change in the angular momentum is #=0.13kgm^2s^-1#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

The mass, #m=5kg#

For a cylinder, #I=m((r_1^2+r_2^2))/2#

So, #I=5*((0.04^2+0.05^2))/2=0.01025kgm^2#

The change in angular momentum is

#DeltaL=IDelta omega#

The change in angular velocity is

#Delta omega=(9-7)*2pi=(4pi)rads^-1#

The change in angular momentum is

#DeltaL=0.01025*4pi=0.13kgm^2s^-1#