A cylinder has inner and outer radii of #4 cm# and #8 cm#, respectively, and a mass of #3 kg#. If the cylinder's frequency of counterclockwise rotation about its center changes from #5 Hz# to #8 Hz#, by how much does its angular momentum change?

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Answer 1 · 2017-01-26T07:43:19

The change is #=0.226kgms^(-1)#

The angular momentum is #L=Iomega#

and #DeltaL=IDeltaomega#

For a cylinder, #I=m/2(r_1^2+r_2^2)#

So, #I=3/2*(0.04^2+0.08^2)=3/2*0.008=0.012kgm^2#

#DeltaL=0.012*(8-5)*2pi=0.012*3*2pi=0.226kgms^(-1)#