A cylinder has inner and outer radii of #5 cm# and #6 cm#, respectively, and a mass of #8 kg#. If the cylinder's frequency of counterclockwise rotation about its center changes from #12 Hz# to #15 Hz#, by how much does its angular momentum change?

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Answer 1 · 2017-07-19T06:05:47

The change in angular momentum is #=0.17kgm^2s^-1#

The angular momentum is #L=Iomega#

For a cylinder, #I=m(r_1^2+r_2^2)/2#

So, #I=3*(0.05^2+0.06^2)/2=0.00915kgm^2#

The change in angular velocity is

#Delta omega=(15-12)*2pi=6pirads^-1#

The change in angular momentum is

#DeltaL=IDelta omega#

#=0.00915*6pi=0.17kgm^2s^-1#