A cylinder has inner and outer radii of #8 cm# and #15 cm#, respectively, and a mass of #3 kg#. If the cylinder's frequency of counterclockwise rotation about its center changes from #14 Hz# to #11 Hz#, by how much does its angular momentum change?

1 Answer
May 24, 2017

Answer:

The change in angular momentum is #=0.82kgm^2s^-1#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

Mass, #m=3kg#

For a cylinder, #I=m((r_1^2+r_2^2))/2#

So, #I=3*((0.08^2+0.15^2))/2=0.04335kgm^2#

The change in angular momentum is

#DeltaL=IDelta omega#

The change in angular velocity is

#Delta omega=(14-11)*2pi=(6pi)rads^-1#

The change in angular momentum is

#DeltaL=0.04335*6pi=0.82kgm^2s^-1#