A cylinder has inner and outer radii of #8 cm# and #16 cm#, respectively, and a mass of #6 kg#. If the cylinder's frequency of counterclockwise rotation about its center changes from #9 Hz# to #7 Hz#, by how much does its angular momentum change?

1 Answer
Feb 2, 2017

Answer:

The answer is #=1.21kgms^(-1)#

Explanation:

The angular momentum is #L=Iomega#

where #I# is the moment of inertia

The change in angular momentum is

#DeltaL=IDelta omega#

#Delta omega# is the change in angular velocity

For a cylinder, #I=m(r_1^2+r_2^2)/2#

So, #I=6*((0.08)^2+0.16^2)/2=0.096kgm^2#

#Delta omega=(9-7)*2pi=4pirads^-1#

#DeltaL=0.096*4pi=1.21kgms^(-1)#