A diver dives into the sea from a height of 35m. His height h meters t seconds after leaving the cliff is given by #h = -4.9² + t + 35#. How long until he reaches the water?
The diver starts at the height of 35 metres. At the point of impact with the water his height is 0.
As I understand things
Acceleration will be 9.81 metres per second squared
So height will be starting distance -( mean velocity times time)
Standard equation is