# A Ferris wheel has a radius of 80 feet. Two particular cars are located such that the central angle between them is 165. To the nearest tenth, what is the length of the intercepted arc between those two cars on the Ferris wheel?

Jul 12, 2018

$230.4 \text{ feet}$

#### Explanation:

$\text{arc length "="circumference "xx"fraction of circle}$

$\textcolor{w h i t e}{\times \times \times \times} = 2 \pi r \times \frac{165}{360}$

$\textcolor{w h i t e}{\times \times \times \times} = \frac{2 \times \pi \times 80 \times 165}{360}$

$\textcolor{w h i t e}{\times \times \times \times} = 230.4 \text{ feet to nearest tenth}$