# A gas at 155 kPa and 25°C has an initial volume of 1.00 L. The pressure of the gas increases to 605 kPa as the temperature is raised to 125°C. What is the new volume?

Nov 21, 2017

$\text{0.34 L}$

#### Explanation:

Ideal gas equation is

$P V = n R T$

$\frac{P V}{T} = n R$

In both the cases $\frac{P V}{T}$ is equal to $n R$

Therefore,

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$

V_2 = (P_1V_1)/T_1 × T_2/P_2

V_2 = (155 cancel"kPa" × "1.00 L")/(298 cancel"K") × (398 cancel"K")/(605 cancel"kPa") = "0.34 L"