A gas cylinder with a volume of 3.00 #dm^3# contains 8.00 moles of oxygen gas at a temperature of 50.0 K. What is the pressure inside the cylinder?

1 Answer
Sep 18, 2016

Answer:

#P~=11*atm#

Explanation:

From the Ideal Gas Law: #P=(nRT)/V# #=# #(8.00*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx50.0*cancel(K))/(3.0*cancel(dm^3)xx1*cancelL*cancel(dm^-3))#.

Given the low temperature, and the small volume of the container, this value is liable to differ from the actual pressure measured in the cylinder. It is a first approximation.