A gas cylinder with a volume of 3.00 dm^3 contains 8.00 moles of oxygen gas at a temperature of 50.0 K. What is the pressure inside the cylinder?

$P \cong 11 \cdot a t m$
From the Ideal Gas Law: $P = \frac{n R T}{V}$ $=$ $\frac{8.00 \cdot \cancel{m o l} \times 0.0821 \cdot \cancel{L} \cdot a t m \cdot \cancel{{K}^{-} 1} \cdot \cancel{m o {l}^{-} 1} \times 50.0 \cdot \cancel{K}}{3.0 \cdot \cancel{{\mathrm{dm}}^{3}} \times 1 \cdot \cancel{L} \cdot \cancel{{\mathrm{dm}}^{-} 3}}$.