# A gas has a pressure of 6.58 kPa at 539 K. What will be the pressure at 211 K if the volume does not change?

Feb 23, 2017

The pressure is $= 2.58 k P a$

#### Explanation:

We apply Gay Lussac's Law

${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$

${P}_{1} = 6.58 k P a$

${T}_{1} = 539 K$

${T}_{2} = 211 K$

${P}_{2} = {T}_{2} / {T}_{1} \cdot {P}_{1}$

$= \frac{211}{539} \cdot 6.58$

$= 2.58 k P a$