# A gas has a volume of 2.00 L at 323 K and 3.00 atm. What will be the new volume if the temperature is changed to 273 K and the pressure is changed to 1 atm?

We use the combined gas law: $\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$. The volume should reasonably REDUCE on compression and cooling.
So ${V}_{2} = \frac{{P}_{1} {V}_{1} {T}_{2}}{{P}_{2} {T}_{1}}$ $=$ $\frac{1.00 \cdot \cancel{a t m} \times 2.00 \cdot L \cdot 273 \cdot \cancel{K}}{3.00 \cdot \cancel{a t m} \times 323 \cdot \cancel{K}}$ $=$ ??L.