Question

A gas has a volume of .590 L at a temperature of -55.0°C. What volume will the gas occupy at 30.0°C?

Answer 1

Approx. `0.8*L`

Explanation:

`"Charles' Law"` holds that `(V)/T=k`, `T="Absolute temperature"`.

At `303.15*K`, `V_2=(V_1T_2)/(T_1)`

`=(0.590*Lxx303*K)/(218*K)` `=` `??L`

`"Volume"` has expanded, as we would expect.