# A gas has a volume of .590 L at a temperature of -55.0°C. What volume will the gas occupy at 30.0°C?

Jun 28, 2016

Approx. $0.8 \cdot L$

#### Explanation:

$\text{Charles' Law}$ holds that $\frac{V}{T} = k$, $T = \text{Absolute temperature}$.

At $303.15 \cdot K$, ${V}_{2} = \frac{{V}_{1} {T}_{2}}{{T}_{1}}$

$= \frac{0.590 \cdot L \times 303 \cdot K}{218 \cdot K}$ $=$ ??L

$\text{Volume}$ has expanded, as we would expect.