# A gas has a volume of 6.0 liters at a pressure of 380 mm Hg. The pressure is increased to gas 760 mm Hg at the same temperature. What is its new volume?

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$
V_2-=(P_1V_1)/P_2=((380*mm*Hg)/(760*mm*Hg*atm^-1)xx6.0*L)/((760*mm*Hg)/(760*mm*Hg*atm^-1) $=$ ??L