# A gas occupies 12.3 at a pressure of 40.0 KPa. What is the volume when the pressure is increased to 60.0 KPa?

##### 1 Answer

May 11, 2017

#### Answer:

The volume is

#### Explanation:

We apply Boyle's Law at constant temperature and constant number of

#P_1V_1=P_2V_2#

The initial pressure is

The initial volume is

The final pressure is

The final volume is

#V_2=P_1/P_2*V_1#

#=40/60*12.3=8.2u#