A kite has vertices at (2, 4), (5, 4), (5, 1), and (0, -1) What is the approximate perimeter of the kite?

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Answer 1 · 2017-10-26T11:44:45

Perimeter of the kite is #16.78 # unit.

Let the vertices of kite are #A(2,4),B(5,4),C(5,1), D(0,-1)#.

We know distance formula as #D= sqrt((x_1-x_2)^2+(y_1-y_2)^2) #

# AB=sqrt(( 2-5)^2+(4-4)^2) = sqrt9 = 3#

# BC=sqrt(( 5-5)^2+(4-1)^2) = sqrt9 = 3#

# CD=sqrt(( 5-0)^2+(1+0)^2) = sqrt29 ~~5.39#

# DA=sqrt(( 0-2)^2+(-1-4)^2) = sqrt29 ~~5.39#

Perimeter of the kite is #AB+BC+CD+DA#

#=3*2+5.39*2 ~~16.78 (2dp) # unit [Ans]