Question

A line passes through (-7, -5) and (-5, 4). How do you write an equation for the line in point-slope form Rewrite the equation in standard form using integers?

Answer 1

The equation of the line in slope-intercept form is `y= 9/2x+53/2.`
The equation of the line in standard form is `9x -2y = -53`

Explanation:

The slope of the line passing through `(-7,-5) and (-5,4)` is `m= (y_2-y_1)/(x_2-x_1)= (4+5)/(-5+7)=9/2`

Let the equation of the line in slope-intercept form be `y=mx+c or y=9/2x+c` The point (-7,-5) will satisfy the equation . So, `-5= 9/2*(-7)+c or c= 63/2-5= 53/2`

Hence the equation of the line in slope-intercept form is `y= 9/2x+53/2.`

The equation of the line in standard form is `y= 9/2x+53/2. or 2y =9x+53 or 9x -2y = -53` {Ans]