A line passes through the point #(8,−3)# and has a slope of #5/4#. Write an equation in slope-intercept form for this line?

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Answer 1 · 2018-02-18T08:08:06

The equation is: # y = 5/4x-13#

The slope-intercept form of a straight line is #y = mx +c#

In this case we have a point, #(x,y)# and the slope, #m# so all we need is a value for #c#.

Substitute into #y=mx+c#

#-3 = 5/4(8) +c#

#-3 = 10+c#

#c=-13#

The equation is: # y = 5/4x-13#

Or you can use the formula for the situation where you have a point, #(x_1, y_1)# and the slope, (m) #rarr" "y-y_1 = m(x-x_1)#

#y -(-3) = 5/4(x-8)#

#y+3 = 5/4x-10#

#y = 5/4x-13#