A machine shop worker records the mass of an aluminum cube as 176 g. If one side of the cube measures 4 cm, what is the density of the aluminum?

Oct 26, 2016

$\text{Density}$ $=$ $\text{Mass"/"Volume}$, so........
$\rho = \frac{176 \cdot g}{4 \cdot c m \times 4 \cdot c m \times 4 \cdot c m}$ $=$ $\frac{176 \cdot g}{64 \cdot c {m}^{3}}$ $=$ ??g*cm^-3.