A mercury atom in the ground state absorbs 20.00 electronvolts energy and is ionized by losing an electron. How much energy does this electron have after the ionization?

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A mercury atom in the ground state absorbs 20.00 electronvolts energy and is ionized by losing an electron. How much energy does this electron have after the ionization?

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Answer 1 · 2018-07-16T06:33:14

After the ionization, the electron has $9.563 eV$ $"9.563 eV"$ of energy.

Explanation:

The kinetic energy $(KE)$ $("KE")$ of a particle is equal to the difference between its absorbed energy $(AE)$ $("AE")$ and its ionization energy $(IE)$ $("IE")$ .

The first ionization energy of $Hg$ $"Hg"$ is $10.4375 eV$ $"10.4375 eV"$ . The absorbed energy is $20.00 eV$ $"20.00 eV"$ .

$KE = AE - IE$ $"KE"="AE"-"IE"$

$KE = 20.00 eV - 10.4375 eV = 9.56 eV$ $"KE"="20.00 eV"-"10.4375 eV"="9.56 eV"$ rounded to two decimal places

https://en.wikipedia.org/wiki/Ionization_energies_of_the_elements_(data_page)

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A mercury atom in the ground state absorbs 20.00 electronvolts energy and is ionized by losing an electron. How much energy does this electron have after the ionization?

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Explanation:

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