A model train with a mass of 1 kg is moving along a track at 24 (cm)/s. If the curvature of the track changes from a radius of 144 cm to 360 cm, by how much must the centripetal force applied by the tracks change?

Jan 10, 2018

The change i centripetal force is $0.024 N$

Explanation:

The centripetal force is

$F = \frac{m {v}^{2}}{r}$

The mass is of the train $m = 1 k g$

The velocity of the train is $v = 0.24 m {s}^{-} 1$

${r}_{1} = 1.44 m$

and

${r}_{2} = 3.60 m$

The variation in the centripetal force is

$\Delta F = {F}_{2} - {F}_{1}$

The centripetal forces are

${F}_{1} = 1 \cdot {0.24}^{2} / 1.44 = 0.04 N$

${F}_{2} = 1 \cdot {0.24}^{2} / 3.60 = 0.016 N$

$\Delta F = 0.04 - 0.016 = 0.024 N$