A model train with a mass of #1 kg# is moving along a track at #6 (cm)/s#. If the curvature of the track changes from a radius of #12 cm# to #8 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Jan 5, 2018

Answer:

The change in centripetal force is #=0.015N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The mass is of the train #m=1kg#

The velocity of the train is #v=0.06ms^-1#

The radii are

#r_1=0.12m#

and

#r_2=0.08m#

The variation in the centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#F_1=1*0.06^2/0.12=0.03N#

#F_2=1*0.06^2/0.08=0.045N#

#DeltaF=0.045-0.03=0.015N#