A model train with a mass of #1 kg# is moving along a track at #6 (cm)/s#. If the curvature of the track changes from a radius of #8 cm# to #15 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Mar 18, 2017

Answer:

The change in centripetal force is #=0.021N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

#m=mass=1kg#

#v=0.06ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=1*0.06^2/0.08=0.045N#

#F_2=1*0.06^2/0.15=0.024N#

#DeltaF=0.045-0.024=0.021N#