A model train with a mass of #1 kg# is moving along a track at #6 (cm)/s#. If the curvature of the track changes from a radius of #12 cm# to #15 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Jun 7, 2017

Answer:

The centripetal force is #=0.006N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=1kg#

speed, #v=0.06ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=1*0.06^2/0.12=0.03N#

#F_2=mv^2/r_2=1*0.06^2/0.15=0.024N#

#DeltaF=0.03-0.024=0.006N#