A model train with a mass of #1 kg# is moving along a track at #6 (cm)/s#. If the curvature of the track changes from a radius of #16 cm# to #15 cm#, by how much must the centripetal force applied by the tracks change?

Question

1312 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-24T12:53:56

The centripeal force changes by #=0.0015N#

The centripetal force is

#F=(mv^2)/r#

mass, #m=1kg#

speed, #v=0.06ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=1*0.06^2/0.16=0.0225N#

#F_2=mv^2/r_2=1*0.06^2/0.15=0.024N#

#DeltaF=0.024-0.0225=0.0015N#