Question

A model train, with a mass of `12 kg`, is moving on a circular track with a radius of `9 m`. If the train's rate of revolution changes from `6 Hz` to `8 Hz`, by how much will the centripetal force applied by the tracks change by?

Answer 1

The change in Centripetal Force will be `48 N to 85.3 N`.

Explanation:

Here:

`m = 12`
`v_1 = 6`
`v_2 = 8`
`r = 9`

We know:

Centripetal Force `= (mv^2)/r`

For first rate of revolution. i.e. `6 Hz`

`CF_1 = (12 *6^2)/9`

`CF_1 = (12 * 36)/9`

`CF_1 = (432)/9`

`CF_1 = 48 N`

For second rate of revolution. i.e. `8 Hz`

`CF_2 = (12 *8^2)/9`

`CF_2 = (12 * 64)/9`

`CF_2 = (768)/9`

`CF_2 = 85.3 N`

The change in Centripetal Force will be `48 N to 85.3 N`.