A model train, with a mass of #12 kg#, is moving on a circular track with a radius of #9 m#. If the train's rate of revolution changes from #6 Hz# to #8 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Mar 11, 2016

Answer:

The change in Centripetal Force will be #48 N to 85.3 N#.

Explanation:

Here:

#m = 12#
#v_1 = 6#
#v_2 = 8#
#r = 9#

We know:

Centripetal Force #= (mv^2)/r #

For first rate of revolution. i.e. #6 Hz#

#CF_1 = (12 *6^2)/9#

#CF_1 = (12 * 36)/9#

#CF_1 = (432)/9#

#CF_1 = 48 N#

For second rate of revolution. i.e. #8 Hz#

#CF_2 = (12 *8^2)/9#

#CF_2 = (12 * 64)/9#

#CF_2 = (768)/9#

#CF_2 = 85.3 N#

The change in Centripetal Force will be #48 N to 85.3 N#.