A model train, with a mass of #12 kg#, is moving on a circular track with a radius of #1 m#. If the train's rate of revolution changes from #6 Hz# to #4 Hz#, by how much will the centripetal force applied by the tracks change by?

Question

1263 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-03T14:20:26

The centripetal force is #=1895N#

The centripetal force is

#F=mr omega^2#

#m=12kg#

#r=1m#

#Delta omega=(6-4)*2pi=4pirads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=12*1*(4pi)^2#

#=12*16*pi^2#

#=1895N#