A model train, with a mass of #12 kg#, is moving on a circular track with a radius of #1 m#. If the train's rate of revolution changes from #6 Hz# to #4 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Mar 3, 2017

Answer:

The centripetal force is #=1895N#

Explanation:

The centripetal force is

#F=mr omega^2#

#m=12kg#

#r=1m#

#Delta omega=(6-4)*2pi=4pirads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=12*1*(4pi)^2#

#=12*16*pi^2#

#=1895N#