A model train with a mass of #2 kg# is moving along a track at #15 (cm)/s#. If the curvature of the track changes from a radius of #9 cm# to #12 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Jan 17, 2018

Answer:

The change in centripetal force is #=0.125N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The mass is of the train #m=2kg#

The velocity of the train is #v=0.15ms^-1#

The radii are

#r_1=0.09m#

and

#r_2=0.12m#

The variation in the centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#F_1=2*0.15^2/0.09=0.5N#

#F_2=2*0.15^2/0.12=0.375N#

#DeltaF=F_1-F_2=0.5-0.375=0.125N#