A model train with a mass of #2 kg# is moving along a track at #36 (cm)/s#. If the curvature of the track changes from a radius of #9 cm# to #3 cm#, by how much must the centripetal force applied by the tracks change?

Question

931 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-03-25T10:56:10

The change in centripetal force is #=5.76N#

The centripetal force is

#F=(mv^2)/r#

#m=mass=2kg#

#v=0.36ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=2*0.36^2/0.09=2.88N#

#F_2=2*0.36^2/0.03=8.64N#

#DeltaF=8.64-2.88=5.76N#