A model train with a mass of #2 kg# is moving along a track at #9 (cm)/s#. If the curvature of the track changes from a radius of #5 cm# to #25 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Mar 4, 2018

Answer:

The change in centripetal force is #=0.277N#

Explanation:

The centripetal force is

#vecF_C=(mv^2)/r*vecr#

The mass is of the train #m=2kg#

The velocity of the train is #v=0.09ms^-1#

The radii of the tracks are

#r_1=0.05m#

and

#r_2=0.25m#

The variation in the centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#||F_1||=2*0.09^2/0.05=0.324N#

#||F_2||=2*0.09^2/0.25=0.0648N#

#DeltaF=F_1-F_2=0.342-0.0648=0.277N#