A model train, with a mass of #2 kg#, is moving on a circular track with a radius of #4 m#. If the train's rate of revolution changes from #1/4 Hz# to #2/5 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Aug 22, 2017

Answer:

The change in centripetal force is #=7.11N#

Explanation:

The centripetal force is

#F=mr omega^2#

The mass is #m=2kg#

The radius #r=4m#

The change in angular velocity is

#Delta omega=(2/5-1/4)*2pi=(3/10pi)rads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=2*4*(3/10pi)^2#

#=7.11N#