A model train, with a mass of #2 kg#, is moving on a circular track with a radius of #8 m#. If the train's rate of revolution changes from #1/2 Hz# to #2/7 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Mar 13, 2017

Answer:

The change in centripetal force is #=29N#

Explanation:

The centripetal force is

#F=mr omega^2#

#m=2kg#

#r=8m#

#Delta omega=(1/2-2/7)*2pi=3/7pirads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=2*8*(3/7pi)^2#

#=29N#