A model train, with a mass of #2 kg#, is moving on a circular track with a radius of #2/3 m#. If the train's rate of revolution changes from #1/9 Hz# to #1/5 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Jul 6, 2017

Answer:

The change in centripetal force is #=0.42N#

Explanation:

The centripetal force is

#F=mr omega^2#

The mass is #m=2kg#

The radius #r=2/3m#

The change in angular velocity is

#Delta omega=(1/5-1/9)*2pi=(8/45pi)rads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=2*2/3*(8/45pi)^2#

#=0.42N#