A model train with a mass of #3 kg# is moving along a track at #12 (cm)/s#. If the curvature of the track changes from a radius of #5 cm# to #8 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
May 8, 2017

Answer:

The change in centripetal force is #=0.32N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=3kg#

speed, #v=0.12ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=3*0.12^2/0.05=0.86N#

#F_2=mv^2/r_2=3*0.12^2/0.08=0.54N#

#DeltaF=0.86-0.54=0.32N#