A model train with a mass of #3 kg# is moving along a track at #12 (cm)/s#. If the curvature of the track changes from a radius of #5 cm# to #24 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Jan 2, 2018

Answer:

The change in centripetal force is #=0.864N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The mass is of the train #m=3kg#

The velocity is #v=0.12ms^-1#

The radii are

#r_1=0.05m#

and

#r_2=0.24m#

The variation in the centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#F_1=3*0.12^2/0.05=0.864N#

#F_2=3*0.12^2/0.24=0.18N#

#DeltaF=0.864-0.18=0.684N#