A model train with a mass of #3 kg# is moving along a track at #15 (cm)/s#. If the curvature of the track changes from a radius of #15 cm# to #12 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Mar 6, 2017

Answer:

The change in centripetal force is #=0.11N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

#m=mass=3kg#

#v=0.15ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=3*0.15^2/0.15=0.45N#

#F_2=3*0.15^2/0.12=0.56N#

#DeltaF=0.56-0.45=0.11N#