A model train with a mass of #3 kg# is moving along a track at #16 (cm)/s#. If the curvature of the track changes from a radius of #15 cm# to #32 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Oct 30, 2017

Answer:

The change in centripetal force is #=0.27N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The mass, #m=(3)kg#

The speed, #v=(0.16)ms^-1#

The radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=3*0.16^2/0.15=0.512N#

#F_2=mv^2/r_2=3*0.16^2/0.32=0.24N#

#DeltaF=0.512-0.24=0.27N#