A model train with a mass of #3 kg# is moving along a track at #8 (cm)/s#. If the curvature of the track changes from a radius of #4 cm# to #18 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Feb 11, 2017

Answer:

The change in centripetal force is #=0.12N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The variation in centripetal force is

#DeltaF=(mv^2)/(Delta r)#

#=(3*(0.08)^2)/(0.18-0.04)#

#=(3*0.08*0.08)/0.16#

#=0.12N#