A model train, with a mass of #3 kg#, is moving on a circular track with a radius of #8 m#. If the train's rate of revolution changes from #1/9 Hz# to #1/2 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Jun 24, 2017

Answer:

The centripetal force changes by #=143.3N#

Explanation:

The centripetal force is

#F=mr omega^2#

The mass is #m=3kg#

The radius #r=8m#

The change in angular velocity is

#Delta omega=(1/2-1/9)*2pi=(7/9pi)rads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=3*8*(7/9pi)^2#

#=143.3N#