A model train, with a mass of #3 kg#, is moving on a circular track with a radius of #2 m#. If the train's rate of revolution changes from #5/4 Hz# to #1/8 Hz#, by how much will the centripetal force applied by the tracks change by?

1 Answer
Feb 11, 2017

Answer:

The change in centripetal force is #=299.8N#

Explanation:

The centripetal force is

#F=mr omega^2#

The variation in centripetal force is

#Delta F=mr (Delta omega)^2#

#Delta F =3*2*(2pi(5/4-1/8))^2#

#=24 pi^2 (81/64)#

#=299.8N#