A model train with a mass of #4 kg# is moving along a track at #14 (cm)/s#. If the curvature of the track changes from a radius of #84 cm# to #42 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Apr 6, 2017

The change in centripetal force is #=0.094N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=4kg#

speed, #v=0.14ms^-1#

radius, #=r#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=4*0.14^2/0.84=0.093N#

#F_2=4*0.14^2/0.42=0.187N#

#DeltaF=0.187-0.093=0.094N#