A model train with a mass of #4 kg# is moving along a track at #3 (cm)/s#. If the curvature of the track changes from a radius of #54 cm# to #27 cm#, by how much must the centripetal force applied by the tracks change?

Question

1131 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-30T08:21:53

The change in centripetal force is #=0.0066N#

The centripetal force is

#F=(mv^2)/r#

mass, #m=4kg#

speed, #v=0.03ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=4*0.03^2/0.54=0.0067N#

#F_2=mv^2/r_2=4*0.03^2/0.27=0.0133N#

#DeltaF=0.0133-0.0067=0.0066N#